Lagrangian Mechanics Example: Cycloidal Pendulum

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Cycloidal pendulum

In this blog post, I explore Huygens’ solution to the problem of pendulum isochronism. While a standard pendulum keeps near-constant time only for small swings, Huygens realized he could constrain the bob to move along a cycloidal arc, ensuring the period is identical for all amplitudes. The cycloid, described by:

\begin{aligned} x &= R(\theta - \sin\theta) \\ z &= R(1 - \cos\theta) \end{aligned}

with R as the generating circle’s radius, provides a path that corrects the amplitude dependence of a regular pendulum. By carefully shaping cheeks or guides for the string to follow, the pendulum bob is forced to trace this path.

Modeling the mechanics with the Lagrangian framework, I arrive at:

\mathcal{L} = mR^2\dot{\theta}^2(1 - \cos\theta) - mgR(1 + \cos\theta)

The resulting equation of motion, after variable substitution and simplification, matches that of a simple harmonic oscillator,

\ddot{u} + \frac{g}{4R}u = 0

where:

u = \cos\left(\frac{\theta}{2}\right)

The cycloidal constraint yields a period:

T_{osc} = 4\pi\sqrt{\frac{R}{g}}

remaining completely of initial amplitude.

For more insights into this topic, you can find the details here.